Abstract
#define N 10
int source[N] = {10, 20, 30, 40, 50}; // The rest of the elements are initialised to 0
int dest;
dest = source; // illegal!- An array name is a fixed pointer; it points to the first element of the array and thus cannot be altered,
sourceis same as&source[0]. The code above attempts to alterdest, making it point elsewhere
What if I want to make a copy to another array?
Use a for-loop,
for (int i=0; i<N; i++) dest[i] = source[i];.
Important
Using the code snippet example above,
source[2]represents the value30itself, not a pointer or reference to the value30.